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07/10/2012
01:46
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sebastiancb
COlombia
Member
Members
Forum Posts: 23
Member Since:
05/09/2011
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Hello, please, I need to show errors from my database mysql , for example 'Duplicate entry' or 'Already exists' in XML, because I have the way to show errors in JSON but I need to do it in XML.

Source code:

Javascript

var json;
var editMessage = function(response,postdata){
    json   = response.responseText; // response text is returned from server.
    var result = JSON.parse(json); // convert json object into javascript object
    return [result.status,result.message,null];
}
//--------------------------------------
jQuery.jgrid.edit = {
editCaption: "Editar",
bSubmit: "Guardar",
bCancel: "Cerrar",
closeAfterEdit:true,
reloadAfterSubmit:true,
processData: "Processing...",
msg:{required:"El campo es obligatorio"},
afterSubmit:editMessage
};

PHP

$message="Duplicate Entry";

$output['status']  = false;
$output['message'] = $message;
echo json_encode($output);

11/10/2012
17:47
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tony
Sofia, Bulgaria
Moderator
Members

Moderators
Forum Posts: 7721
Member Since:
30/10/2007
sp_UserOfflineSmall Offline

Hello,

Use console.log to see the response.

I'm not sure that boolean true is evaluated as tru.

Try this in FireFox with FireBug installed

var editMessage = function(response,postdata){
    json   = response.responseText; // response text is returned from server.
    var result = JSON.parse(json); // convert json object into javascript object

    console.log(result);
    return [result.status,result.message,null];
}

Regards

For professional UI suites for Java Script and PHP visit us at our commercial products site - guriddo.net - by the very same guys that created jqGrid.

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