jQuery Grid Plugin - jqGrid

Yes but can you change it after the grid is made? Or add some columns dynamicly

Ok I found a sollution. It wasn't that difficult and just to let you all know it does work.

The php end:

function test(){ 
        $test->colnames = array('Id','Rights', 'Username', 'Password', 'First Name', 'Last Name', 'E-Mail');
           $test->colmodel = array("{name:'id',index:'id', editable:false,editoptions:{readonly:true,size:10}}",
           "{name:'role_id',index:'role_id', editable:true,editoptions:{size:25}}",
        "{name:'username',index:'username', editable:true,editoptions:{size:25}}",
        "{name:'password',index:'password', editable:true,editoptions:{size:25}}",
        "{name:'first_name',index:'first_name', editable:true,editoptions:{size:25}}",
        "{name:'last_name',index:'last_name', editable:true,editoptions:{size:25}}",
        "{name:'email',index:'email', editable:true,editoptions:{size:25}}");
        echo json_encode($test);
    }

The javascript end:

$.ajax({
      url: basedir+"users/test",
      dataType: 'json',
      success: function(data){
                    var colnames = data.colnames;
                    var colmodel = data.colmodel;
                    $("#usergrid").jqGrid({       
                           url: 'path',
                           datatype: "json",
                           colNames: colnames,
                           colModel: colmodel,
                           .....
                    });

      }

});

So you can create the full colModel en colNames in the backend, then call it through ajax and then build the grid wih that data.

I hope this is helpfull to anyone.

Kind Regards,

Karel-Jan