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JQGrid 4.5.4 - Column Chooser Bug
20/12/2013
19:21
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pposgate
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20/12/2013
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We found a bug with the "Column Chooser" feature in JQGrid 4.5.4.  This bug can be demonstrated in JQGrid's demo-page, under the "New in version 3.6″ section, in the "Column Chooser" example.  We are using Windows7, and repeated the bug while using IE8, IE9, IE10, IE11, and FF26. 

I will now explain the steps to repeat this bug using screenshots…

Step 1: Start with…

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Step 2: Click the "Columns" button to open the Column Chooser…

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Step 3: Click "Remove All"…

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Step 4: Add the "Client" column back…

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Step 5: Click the "Ok" button, and now you see the bug (eg: the grid doesn't show the "Client" column)…

Step 6: Moving along….   Click the "Column Chooser" button again….

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Step 7: Add the "Client" column back….

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Step 8: Click the "Ok" button again…. Now it works!

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08/09/2014
22:17
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bkwdesign
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I have an implementation of jqGrid 4.5.4 and I have found this bug, too, independently of this thread. It is indeed peculiar. I just wanted to add my voice to this issue.

09/09/2014
16:55
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OlegK
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I can confirm the bug. It's important to mention that the problem don't exist if one uses old versions of jQuery (for example 1.8.3) and old version of jQuery UI (for example 1.8.24). I prepared the demo which uses the old versions of jQuery and jQuery UI and it seems to work without any problems.

Then I get the last version of jQuery UI Multiselect plugin from github and made some small changes to use [selected] selector. I changed two lines of jqGrid code too to do the same. As the result the code seems to work for both new jQuery (1.11.1) and new jQuery UI (1.11.0): the new demo. It's important to remark that the demo which uses modified ui.multiselect.js and modified jqGrid works with old versions of jQuery (1.8.3) and jQuery UI (1.8.24).

The modification which I made in jqGrid was replacing the line

if (this.selected) {

to the line

if ($(this).is("[selected]")) {

and replacing the line

$('option:selected',select).each(function() { perm.push(parseInt(this.value,10)); });

to the line

$('option[selected]',select).each(function() { perm.push(parseInt(this.value,10)); });

 In the same way I modified the line 

var options = that.element.find('option').not(":selected");

of ui.multiselect.js to the following line

var options = that.element.find('option').not("[selected]");

and another lines 

var item = that._getOptionNode(this).appendTo(this.selected ? that.selectedList : that.availableList).show();

if (this.selected) that.count += 1;

to the lines

var isSelected = $(this).is("[selected]"),
    item = that._getOptionNode(this).appendTo(isSelected ? that.selectedList : that.availableList).show();

if (isSelected) that.count += 1;

One can get the modified version of ui.multiselect.js here.

Best regards
Oleg

13/09/2014
12:41
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tony
Sofia, Bulgaria
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Hello,

 

The good news is that I will change the code in jqGrid.

The bad news is  that it is unknown if this will be fixed in multi-select plugin.

 

Regards

Tony

For professional UI suites for Java Script and PHP visit us at our commercial products site - guriddo.net - by the very same guys that created jqGrid.

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