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08:47
09/11/2008
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Hi,
I installed the last Version of jQGrid,
I wrote an example html, and an example.php.
The grid displays fine, but my example.php is never called
Example.php works fine if i call it directly from the browser (produces a json string)
the java script for jquery reacts correctly if i modifiy some parameters.
imagpath: 'themes/sand/images' produces a java console error
i tried many combination with url: .... (example.php is in the same directory than example.html'. I checked all the includes. No way to get example.php to run.
Any Ideas ?
Thanks
07:19
Moderators
30/10/2007
Offline
Hello,
Use FireBug console to see from where is called example.php.
Regards
Tony
For professional UI suites for Java Script and PHP visit us at our commercial products site - guriddo.net - by the very same guys that created jqGrid.
08:21
09/11/2008
Offline
Problem Solved :
Firefox was blocking the request
in a new tab, select url "about.config"
select the line : extensions.firefox.console.allowDoublePost.. set it true.
Other bug detected in my own code : don't use "echo" or "print" in the PHP program. it destroys the structure of json string awaited by jqgrid.
09:47
13/11/2008
Offline
Mike said:
…
Other bug detected in my own code : don’t use “echo†or “print†in the PHP program. it destroys the structure of json string awaited by jqgrid.
Best solution here is to create the desired array and then return the result of json_encode($dataarray).
Cheers,
P.
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