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eval()`ed subgrid fails

23/09/2008
10:11

sledge

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07/04/2008

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Hello,

I am creating grid and its subgrid dynamically, by posting ajax request and doing eval(response); (i do this because a schema of a subgrid depends on which row i have clicked).

With main grid everything works fine. After I expand row, subgrid gets created OK (eval from JSP generated action), too, but writes out Loading and stays like that.

It should add a row of data, which does get fetched (firebug reports correct response of the json row I need to see in a subgrid).

However, firebug shows an error:

ts.rows is undefined

addJSONData()grid.base-min.js (line 87)

complete()grid.base-min.js (line 99)

complete()jquery.js (line 11)

e()jquery.js (line 11)

[Image Can Not Be Found]$(ts.rows[i]).after(row);if(afterInsRow){ts.p.afterInsertRow(row.id,rd);}

I have viewed all code which is being eval()`ed -- it is ok (i.e., it is the same action in JSF that is rsponsible to create grid and its subgrids, it manages changing of the grid_id via parameters, so I have checked -- all jQuery('#<grid_or_subgrid_id>'). .. references are OK.

I do not know where to look for more...

Please help, thanks huge,

sledge

23/09/2008
15:36

sledge

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07/04/2008

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To add more information in the matter, which is a major blocker for me..:

I have tried even swapping grid with its subgrid – same results (Loading forever).

It would appear that it breaks on the bigger JSON data being somehow invalid. But it consists only from 10 elementary not-corrupted strings (for 10 columns) -- that's for the subgrid. (remember -- the same code generates the json from the DB query). Main grid contains 3 columns only.

If I replace subgrid with hardcoded xmlstring, everything shows ok. jsonstring meanwhile cannot be shown.

Is there a problem with many-columned json strings?

Probably -- no, because the biggest mistery in this was that JSON data with 10 values was displayed OK, when the subgrid was still hardcoded in the .html file. Once I have refactoried it to be eval()`ed, it stopped showing data.

Well, I hope I'll break through this one..

Standing by, pals,

--
sledge

24/09/2008
04:57

tony

Sofia, Bulgaria

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30/10/2007

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Hello,

The simple test is:

Do not use jqGrid. Simulate ajax request for the problem data and see

what it is. If all is ok - look in the jsonReader and look if

you return the correct data.

Regards

Tony

For professional UI suites for Java Script and PHP visit us at our commercial products site - guriddo.net - by the very same guys that created jqGrid.

24/09/2008
11:14

sledge

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07/04/2008

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Thank you. With clear head today I have solved the problem: it was an erroneous backreference to the ever generated subgrid id.

case closed, pardon for that

--
sledge

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