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13:28

17/06/2009

I was tring to use a sub grid but it has not been working. I backtraced with the server and the server is responding with Correct format xml.Please Help
(i also tried to check myself it does not show .'("#"+subgrid_id)'does not give any element .
Please help.
this is the grid code:-
jQuery("#list1").jqGrid({
url:url_const,
datatype: "xml",
colNames:colnames,
colModel:colmodel,
mtype:'GET',
height:'350',
rowNum:15,
rowList:[10,15,20,25,30],
imgpath: "themes/green/images",
pager: jQuery('#pager1'),
sortname: 'ip',
viewrecords: true,
sortorder:"desc" ,
caption:"Session Comparision Table",
subGrid:true,
subGridRowExpanded: function(subgrid_id, row_id)
{
var subgrid_table_id, pager_id;
subgrid_table_id = subgrid_id+"_t";
pager_id = "p_"+subgrid_table_id;
var tempval="<table id='"+subgrid_table_id+"' class='scroll'></table><div id='"+pager_id+"' class='scroll'></div>";
$("#"+subgrid_id).html(tempval);
jQuery("#"+subgrid_table_id).jqGrid({
url:suburl_const+"&id="+row_id,
datatype: "xml",
mtype:'GET',
colNames: subcolname,
colModel: subcolmodel,
rowNum:5,
pager: pager_id,
imgpath: "themes/sand/images",
sortname: 'port',
sortorder: "asc",
height: '100%' })}
});
});
05:43

Moderators
30/10/2007

Hello,
This mean that you do not have a proper rowid set in the main grid.
subgrid_id is a combination of the rowid+"_id".
Regards
Tony
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