Forum


15:16

Moderators
30/10/2007

Hello,
You can disable the build in hovering of rows with:
hoverrows : false and write your own procedure after the grid is created something like this
$("#grid").bind('mouseover',function(e) {
/// the current row is determined like this
ptr = $(e.target).closest("tr.jqgrow");
/// do somethuing hover the cell
return false;
}).bind('mouseout',function(e) {
/// do other things
return false;
});
Regards
For professional UI suites for Java Script and PHP visit us at our commercial products site - guriddo.net - by the very same guys that created jqGrid.
Most Users Ever Online: 715
Currently Online:
59 Guest(s)
Currently Browsing this Page:
1 Guest(s)
Top Posters:
OlegK: 1255
markw65: 179
kobruleht: 144
phicarre: 132
YamilBracho: 124
Renso: 118
Member Stats:
Guest Posters: 447
Members: 11373
Moderators: 2
Admins: 1
Forum Stats:
Groups: 1
Forums: 8
Topics: 10592
Posts: 31289
Newest Members:
, razia, Prankie, psky, praveen neelam, greg.valainis@pa-tech.comModerators: tony: 7721, Rumen[Trirand]: 81
Administrators: admin: 66
I would like to use jQuery UI icons as action buttons in the last column of my grid. I have a column formatter making a div and a load of spans with ui-state-default, ui-icon classes etc.
Thing is, when the user selects a row, my icons get highlighted too.
I was wondering if there is any way I could hook into an event so that I can write my own selection routine?
I think I want to apply ui-state-highlight on a per-cell basis so that I can miss out my “Actions” cell. That is I _do_ want the row to be selected, I just want to control how it looks.
Yes, I can just use "standard buttons" - I am using them at the moment. But they look kinda rubbish compared with all the jQuery UI stuff that surrounds them.
Of course there may be _another_ way to achieve what I want.