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17:47

06/12/2009

Sorry my english is very pool.
when i try to use jqgrid with the JSON data, i get this picture:
i use a java servlet to provide the json data. and the data like this:
{"page":1,"records":4,"rows":[{"age":24,"id":0,"name":"talen"},{"age":24,"id":1,"name":"talen"},{"age":24,"id":2,"name":"talen"},{"age":24,"id":3,"name":"talen"}],"total":1}
and my sourcecode of the page is :
$(function() {
jQuery("#jsonmap1").jqGrid({
url:'jsonServlet',
datatype: "json",
colNames:['id','name', 'age'],
colModel:[
{name:'id',index:'id', width:100},
{name:'name',index:'name', width:200},
{name:'age',index:'age', width:100}],
rowNum:10,
rowList:[10,20,30],
sortname: 'id',
viewrecords: true,
pager: '#pjmap1',
sortorder: "desc",
jsonReader: { repeatitems : false},
height: '100%'
});
jQuery("#jsonmap1").jqGrid('navGrid','#pjmap1',{edit:false,add:false,del:false});
});
......
<table id="jsonmap1" class="scroll" cellpadding="0" cellspacing="0"></table>
<div id="pjmap1" class="scroll" style="text-align:center;"></div>
what is wrong? please help me, thx
18:11

Moderators
30/10/2007

Hello,
Sorry, but I can not see the picture.
Did you have downloaded all the needed editing modules?
Best Regards
Tony
For professional UI suites for Java Script and PHP visit us at our commercial products site - guriddo.net - by the very same guys that created jqGrid.
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