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How to define groupText if groupField has more as one items

Tags: grouping

12/09/2010
18:56

OlegK

Germany

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10/08/2009

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Hi Tony,

I could not find a way how to display the second item from the groupField. For example if I change in the example from http://www.ok-soft-gmbh.com/jq.....m the groupField : ['subSource'] to

groupField : ['source', 'subSource']

I could not modify

groupText: ['{0} - {1} Item(s)']

in any way so that the information about the second item ('subSource') will be displayed. What would be mean groupText: ['{0} - {1} Item(s)', '{0} - {1} Item(s)'] for example? Where should be displayed the second element of the groupText array?

The the worst case it seems to me more correct to display the last grouping index in the groupText. For example if you will group by 'source' and 'subSource' (see the link to the example above), then the 'subSource' names are more informative as the information from the 'source'. Isn't it?

It could be that the grouping with more as one grouping fields not yet works in jqGrid?

Thanks
Oleg

04/08/2011
00:50

kccarter

Salt Lake City, UT

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04/08/2011

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you can enable multiple mapping for the group by text with the following code:

groupingRender: function(c, b) {
 return this.each(function() {
 var a = this, d = a.p.groupingView, e = "", g = "", j, m = "", n = [], q, k;
 if (!d.groupDataSorted) {
 d.sortitems[0].sort();
 d.sortnames[0].sort();
 if (d.groupOrder[0].toLowerCase() == "desc") {
 d.sortitems[0].reverse();
 d.sortnames[0].reverse()
 }
 }
 m = d.groupCollapse ? d.plusicon : d.minusicon;
 m += " tree-wrap-" + a.p.direction;
 for (k = 0; k < b; ) {
 if (a.p.colModel[k].name == d.groupField[0]) {
 q = k;
 break
 }
 k++
 }
 f.each(d.sortitems[0], function(h, l) {
 j = a.p.id + "ghead_" + h;
 g = "";
 try {
 n.push(d.groupText[0]);
 jQuery(d.groupField).each(function(index, field) {
 n.push($($('td', $(c[l][0].join()))[a.p.colNames.indexOf(field)]).text());
 });
 } catch (u) {
 n = [d.groupText[0], d.sortnames[0][h]];
 }
 n.push(c[l].length);
 e += '<tr id="' + j + '" role="row" class= "ui-widget-content jqgroup ui-row-' + a.p.direction + '"><td colspan="' + b + '">' + g + f.jgrid.format.apply(this, n) + "</td></tr>";
 for (h = 0; h < c[l].length; h++)
 e += c[l][h].join("");
 if (d.groupSummary[0]) {
 h = "";
 if (d.groupCollapse && !d.showSummaryOnHide)
 h = ' style="display:none;"';
 e += "<tr" + h + ' role="row" class="ui-widget-content jqfoot ui-row-' + a.p.direction + '">';
 h = d.summaryval[0][l];
 for (var o = a.p.colModel, p, r = c[l].length, i = 0; i < b; i++) {
 var s = "<td " +
 a.formatCol(i, 1, "") + "> </td>", t = "{0}";
 f.each(h, function() {
 if (this.nm == o[i].name) {
 if (o[i].summaryTpl)
 t = o[i].summaryTpl;
 if (this.st == "avg")
 if (this.v && r > 0)
 this.v /= r;
 try {
 p = a.formatter("", this.v, i, this)
 } catch (v) {
 p = this.v
 }
 s = "<td " + a.formatCol(i, 1, "") + ">" + f.jgrid.format(t, p) + "</td>";
 return false
 }
 });
 e += s
 }
 e += "</tr>"
 }
 n = [];
 });
 f("#" + a.p.id + " tbody:first").append(e);
 e = null;
 }

04/08/2011
02:33

kccarter

Salt Lake City, UT

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Forum Posts: 6

Member Since:
04/08/2011

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in order to maintain compatibility with IE the following needs to be done

if (Array.prototype.indexOf === undefined) {
 $.extend(Array.prototype, (function () {
 function indexOf(item) {
 for (var i = 0; i < this.length; i++) {
 if (this[i] === item) {
 return i;
 }
 }
 return -1;
 }

        return {
            indexOf: indexOf
        };
    })());
}

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