jQuery Grid Plugin - jqGrid

Hello,

I´ve the same problem as battancs.

I've a grid like this:

("#grid_plantilla").jqGrid({
        url: "v93PlantillaMatHomologadosInOP.do?action=",
        datatype: "json",
        scroll: true,
        width: 895,
        height: 'auto',    
        mtype: 'POST',
        colNames: ['id','codCampo','descripcion','valor','tipDato','decimales','longitud','tabla','multiple','oblig'],        
        colModel: [{name:'id',index:'1',width:100,editable: true},//hidden:true, , editable:false
                   {name:'codCampo',index:'2',width:100,editable: true},//hidden:true,, editable:false
                   {name:'descripcion',index:'3',width:300,editable: true},
                    {name:'valor',index:'4',width:400,editable: true},
                   {name:'tipDato',index:'5',width:500,editable: true},
                     {name:'decimales',index:'4',width:500,editable: true},
                     {name:'longitud',index:'4',width:500,editable: true},
                     {name:'tabla',index:'4',width:500,editable: true},
                     {name:'multiple',index:'4',width:500,editable: true},
                     {name:'oblig',index:'4',width:500,editable: true, hidden:true}],
        viewrecords: true,
        imgpath: jsPath,
        multiselect: true,
        multiboxonly: true,        
        pager: $("#pager_grid_plantilla"),
        editurl:'clientArray',    
        gridComplete: function(){
            repintarPlantilla();
        },
        ondblClickRow: function(){
            editarFilaPlantilla();
        }
    });

And when I want to edit a row I do this:

$("#grid_plantilla").jqGrid('editGridRow',filaSeleccionada,{height:280, bSubmit: "hola",reloadAfterSubmit:false});

But whe I check the button submit I get this error:

error Status: 'Not Found'. Error code: 404

[Image Can Not Be Found]

[Image Can Not Be Found]

Could you hel me?

Thanks you very much

Hello,

Thanks you Tom it was very usefull for me.

Could you help me with another problem?

I ned to feed a grid's column's cells with a combobox, a checkbox or a textbox, depending of a concrete value i'm reading from database.

In order to do this I've created a grid with 5 columns, the first column is always visible and others columns are always invisible (the second column type is select, third is checkbox, fourth is textbox and the fifth column has the codes selected in the combo just in case you use it) . The first column contains the value fed by the hidden columns.

I use the code "plantillaGrid.editGridRow( numFila, {height:280, bSubmit: "hola",reloadAfterSubmit:false} )" to edit a row and, depending the row I select, I hide or show one of the columns wich are hidden in the original grid.

For example I've a grid like this.

1st record has to be a checkbox

2nd record has to be a multiple select

3rd record has to be a textbox

When I edit the first record I hide the first column and show the third one. I check the checkbox and when I click Submit button, the selected row has to be changed according to the values I've entered in the window opened by the editGridRow sentence. After doing this, the first column must be updated to "Yes".

When I edit the second record I hide the first column and show the second one. I select all the values I want in the combobox and, when I click in submit button, after updating the row, I´ve to put  the selected values on the combobox in the first column, and the codes selected in the combo in the 5th column...

I've tried using the afterSubmit, afterShowForm, onclickSubmit and onClose events, but none of them seem to fit my concrete needs: they always seem to be triggered when jQgrid hasn't still changed the edited row's values with the values entered in the new window.

Thanks you very much,

Izaskun

Thanks you very much Tony.