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09:43
09/11/2009
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Is there a way (by config or by jquery code) to set the column widths to reasonable defaults, much like the regular html table behaves when you don't set any explicit column widths?
03:22
Moderators
30/10/2007
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Hello,
Many times disscused - the answer is No.
Regards
Tony
For professional UI suites for Java Script and PHP visit us at our commercial products site - guriddo.net - by the very same guys that created jqGrid.
04:46
09/11/2009
Offline
I take that as a challenge 
I'm getting closer: I can calculate an approximation of the width for a specific column by finding the width of, for example, the first cell:
<div id=”measure” style=”visibility:hidden”/>
and in loadComplete:
$('#measure').html('<span>' + $('#treegrid2 tbody tr:first td:eq(1)').text() + '</span>');
alert($('#measure span').width());
I realize that the cell selection should use getCell, but that always returns false for me, I'll keep poking at that. So how do I use this width value to set the width of a column after load? Between http://www.trirand.com/jqgridw.....;s=getcell I don't see anything that fits the bill.
10:11
Moderators
30/10/2007
Offline
Hello,
You should consider my answer NO as challenge too 
Tony
For professional UI suites for Java Script and PHP visit us at our commercial products site - guriddo.net - by the very same guys that created jqGrid.
08:02
09/11/2009
Offline
I'm currently looking at something like this (call with resizeColumns('#yourgrid', ['colname1', 'colname2']):
var grid = $(id);
var cfgstring = grid.jqGridExport({'exptype': 'jsonstring'});
//var config = JSON.parse(cfgstring, function(k, v) { return v; });
eval('config = ' + cfgstring);
var rows = grid.getRowData();
var widths = new Array();
for (col in cols) {
colname = cols[col];
widths[colname] = 0;
}
for (rownum in rows) {
row = rows[rownum];
for (col in cols) {
colname = cols[col];
$('#measure').html('<span>' + row[colname] + '</span>');
w = $('#measure span').width();
if (w > widths[colname]) {
widths[colname] = w;
}
}
}
var colModel = config['grid']['colModel'];
for (col in colModel) {
if (colModel[col]['name'] in widths) {
colModel[col]['width'] = widths[colModel[col]['name']];
}
}
grid.jqGridImport({'imptype':'jsonstring', 'impstring':JSON.stringify(config)});
}
Currently, jqGridExport({'exptype': 'jsonstring'}) throws an error:
Source File: http://projecten.han-imao.nl:8000/agilito/js/jquery.jqgrid/js/jquery.jqGrid.min.js
Line: 10
I know the eval is stupid, but when I use JSON.parse I just get
Any clues appreciated.
00:31
Moderators
30/10/2007
Offline
Hello,
If you try this with FireFox 3.5 on Linux or FireFox and Safary on Mac there is a bug which is corrected - also it is not actually a bug in jqGrid, but in FireFox.
Regards
Tony
For professional UI suites for Java Script and PHP visit us at our commercial products site - guriddo.net - by the very same guys that created jqGrid.
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