jQuery Grid Plugin - jqGrid

Hi all
thanks for this great tool.
sorry, I tried to solve my problem reading the other posts but I can't get this working.

Example:

Mysql DB Table
tbl_local (idtbl_local; Description) values (1,Ombro; 2,Cotovelo; 3,Braco....)
tbl_classf(idtbl_classf; Description; id_local) values (2,'Classificação 102', 1; 3,'Classificação 6',1)

relationship: tbl.tbl_classf.id_local<->tbl_local.idtbl_local

I'm using a view to upload the values from database to jqgrid:
CREATE VIEW `ortodb`.`view_classf_local` AS select `a`.`idtbl_classf` AS `ID`,`a`.`description` AS `Description`,`a`.`id_local` AS `id_local`,`b`.`idtbl_local` AS `id_join_local`,`b`.`Description` AS `Local_Description` from (`ortodb`.`tbl_classf` `a` left join `ortodb`.`tbl_local` `b` on((`a`.`id_local` = `b`.`idtbl_local`)))

 

I try to use jqgrid to edit/add the tbl_classf populating the edit form with the select "local" (tbl_local.Description) and update the id_local from tbl_classf

 

I need help to create a select option with all 'local' options, but showing the default value selected.
and finally update and add to database.
thanks in advance.

sorry by my bad english.
I'm Portuguese.