Forum
22:47
21/10/2010
I recently started using jqgrid, adding it to one of our projects. In our project we have several prototypes defined for the Array object ( obj.contains(x), etc ). I added the grid control and it works fine, but when I added the grouping module with summary footers it returns an error "jqGrid – No such method: groupingCalculations.undefined". I basically have a few records with the Summary Footers, since we need aggregates for several fields:
var mydatax = [
{ 'Eureka ID': '154896', 'Agent': 'Felix Z' }
];
jQuery("#list47″).jqGrid({
data: mydatax,
datatype: "local",
height: 'auto',
rowNum: 50,
//rowList: [10, 20, 27],
colNames: ['Eureka ID', 'Agent'],
colModel: [
{ name: 'Eureka ID', index: 'Eureka ID', width: 80, summaryType: 'avg', summaryTpl: '<b>AVG: {0}</b>' },
{ name: 'Agent', index: 'Agent', width: 80 }
],
pager: "#plist47″,
viewrecords: true,
sortname: 'Agent',
grouping: true,
groupingView: {
groupField: ['Agent'],
groupSummary: [true],
groupColumnShow: [true],
groupText: ['<b>{0}</b>'],
groupCollapse: false,
groupOrder: ['asc']
},
caption: "Grouping Array Data"
});
And, a simple prototype will do the trick:
Array.prototype.junk = function(v) {
return this.length;
}
You must also have "groupSummary: [true]". I'm using the latest jquery.jqGrid-3.8. Anybody have any idea how to get around this, other than "don't use the prototypes!"?
Thanks,
Ben
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