jQuery Grid Plugin - jqGrid

Hello Tony,

You are right, this is a workaround. In the question which initialized my post here it was used as a solution. I posted this problem here because I look at the problem from a little other side.

It seems to me the problem which appears once will appear next time for other users. It would be better if one make jqGrid code a little more robust in case of missing some input information. I mean that it would be nice if jqGrid be able to display empty table not only for

{"page":1, "records":0, "total":1, rows:[]}

but also for

{"page":1, "records":0, "total":1}

{"page":0, "records":0, "total":0}

{"records":0}

or

{}

The most part of codes use already default values for missing input parameters. For example you use

    ts.p.page = $.jgrid.getAccessor(data,dReader.page) || 0;
    lp = $.jgrid.getAccessor(data,dReader.total);
    ts.p.lastpage = lp === undefined ? 1 : lp;
    ts.p.records = $.jgrid.getAccessor(data,dReader.records) || 0;
    ts.p.userData = $.jgrid.getAccessor(data,dReader.userdata) || {};

so you tried already to make the code working for undefined input data. The change of the code

    drows = $.jgrid.getAccessor(data,dReader.root);
    if (!drows) { return; }

to one line

    drows = $.jgrid.getAccessor(data,dReader.root) || {};

seems for me the best pragmatic solution of the problem which just follow the other parts of code.

Best regards
Oleg