jQuery Grid Plugin - jqGrid - Topic: saveRow() - how to send "real" id? http://www.trirand.com/blog/?page_id=393/help/saverow-how-to-send-real-id Simple:Press Version 5.7.5.3 Ilyich on saveRow() - how to send "real" id? http://www.trirand.com/blog/?page_id=393/help/saverow-how-to-send-real-id#p24682 Help http://www.trirand.com/blog/?page_id=393/help/saverow-how-to-send-real-id#p24682 Oh, it's really my fault. Thanks for correcting me OlegK! 🙂

]]> Tue, 20 Sep 2011 06:59:20 +0300 OlegK on saveRow() - how to send "real" id? http://www.trirand.com/blog/?page_id=393/help/saverow-how-to-send-real-id#p24680 Help http://www.trirand.com/blog/?page_id=393/help/saverow-how-to-send-real-id#p24680 Typical origin for the problems which you describe are wrong filled jqGrid. If the input (JSON or XML data) of jqGrid has no id information or has the information, but in wrong way, jqGrid use integers 1,2,3... as the row ids. So I recommend you to verify how you fill the grid.

Regards
Oleg 

]]> Tue, 20 Sep 2011 00:16:03 +0300 Ilyich on saveRow() - how to send "real" id? http://www.trirand.com/blog/?page_id=393/help/saverow-how-to-send-real-id#p24677 Help http://www.trirand.com/blog/?page_id=393/help/saverow-how-to-send-real-id#p24677 Greetings.

I have a problem with sending data to server via saveRow(). So, when i try to save row information, all data sent is correct, excepting ID field. SaveRow() sends not information from ID field but the number of row in grid. (i.e if You select 2nd row then id will be 2) I think of using extraparam parameter of SaveRow() to add information of "real" id, but maybe there is another way to solve a problem?

PS Sorry for my bad English, it's not a native language for me. Please feel free to correct me if there was any mistakes in my post.

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