ggcristian on jqgrid help - php json fill table

Tue, 18 Mar 2014 13:57:14 +0200

I have also tried the demo using the folowing files:

HTML:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DT.....t;>
<html xmlns="http://www.w3.org/1999/xhtml&q.....t;>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>tabele</title>
<link rel="stylesheet" type="text/css" media="screen" href="jquery-ui.css" />
<link rel="stylesheet" type="text/css" media="screen" href="css/ui.jqgrid.css" />
<script src="jquery.js" type="text/javascript"></script>
<script src="js/i18n/grid.locale-ro.js" type="text/javascript"></script>
<script src="js/jquery.jqGrid.min.js" type="text/javascript"></script>
<script src="js/ui.multiselect.js" type="text/javascript"></script>
</head>
<body>
<table id="list2"></table>
<div id="pager2"></div>
<script>
jQuery("#list2").jqGrid({
   url:'server.php?q=2',
   datatype: "json",
   colNames:['Inv No','Date', 'Client', 'Amount','Tax','Total','Notes'],
   colModel:[
   {name:'id',index:'id', width:55},
   {name:'invdate',index:'invdate', width:90},
   {name:'name',index:'name asc, invdate', width:100},
   {name:'amount',index:'amount', width:80, align:"right"},
   {name:'tax',index:'tax', width:80, align:"right"},
   {name:'total',index:'total', width:80,align:"right"},
   {name:'note',index:'note', width:150, sortable:false}
           ],
   rowNum:10,
   rowList:[10,20,30],
   pager: '#pager2',
   sortname: 'id',
   viewrecords: true,
   sortorder: "desc",
   caption:"JSON Example"
   });
   jQuery("#list2").jqGrid('navGrid','#pager2',{edit:false,add:false,del:false});
</script>
</body>
</html>

server.php

<?php
$dbhost = 'localhost';
$dbuser= 'root';
$dbpassword = 'dbpass';
$database = 'griddemo';
$page = $_GET['page']; // get the requested page
$limit = $_GET['rows']; // get how many rows we want to have into the grid
$sidx = $_GET['sidx']; // get index row - i.e. user click to sort
$sord = $_GET['sord']; // get the direction
if(!$sidx) $sidx =1; // connect to the database
$db = mysql_connect($dbhost, $dbuser, $dbpassword) or die("Connection Error: " . mysql_error());
mysql_select_db($database) or die("Error conecting to db.");
$result = mysql_query("SELECT COUNT(*) AS count FROM invheader a, clients b WHERE a.client_id=b.client_id");
$row = mysql_fetch_array($result,MYSQL_ASSOC);
$count = $row['count'];
if( $count >0 ) { $total_pages = ceil($count/$limit); }
else { $total_pages = 0; }
if ($page > $total_pages) $page=$total_pages;
$start = $limit*$page - $limit; // do not put $limit*($page - 1)
$SQL = "SELECT a.id, a.invdate, b.name, a.amount,a.tax,a.total,a.note FROM invheader a, clients b WHERE a.client_id=b.client_id ORDER BY $sidx $sord LIMIT $start , $limit";
$result = mysql_query( $SQL ) or die("Couldn t execute query.".mysql_error());
$responce->page = $page;
$responce->total = $total_pages;
$responce->records = $count;
$i=0; while($row = mysql_fetch_array($result,MYSQL_ASSOC)) {
$responce->rows[$i]['id']=$row[id];
$responce->rows[$i]['cell']=array($row[id],$row[invdate],$row[name],$row[amount],$row[tax],$row[total],$row[note]);
$i++; }
echo json_encode($responce);
?>

The result is the same: the grid is rendered empty.

ggcristian on jqgrid help - php json fill table

Tue, 18 Mar 2014 13:38:40 +0200

Hi,

I have some troubles getting the grid populated with the data retrieved from the database.

my HTML:

jQuery("#list2").navGrid('#pager2', {

edit: true, add: true, del: true, search: true
});

});
</script>
</head>
<body>
<table id="list2"></table>
<div id="pager2"></div>
</body>
</html>

my server.php

<?php
$dbhost = 'localhost';
$dbuser= 'root';
$dbpassword = 'dbpass';
$database = 'dbname';
$page = $_GET['page']; // get the requested page
$limit = $_GET['rows']; // get how many rows we want to have into the grid
$sidx = $_GET['sidx']; // get index row - i.e. user click to sort
$sord = $_GET['sord']; // get the direction
if(!$sidx) $sidx =1;
// connect to the database
$db = mysql_connect($dbhost, $dbuser, $dbpassword) or die("Connection Error: " . mysql_error());
mysql_select_db($database) or die("Error conecting to db.");
$result = mysql_query("SELECT COUNT(*) AS count FROM marfa");
$row = mysql_fetch_array($result,MYSQL_ASSOC);
$count = $row['count'];
if( $count >0 ) { $total_pages = ceil($count/$limit); }
else { $total_pages = 0; }
if ($page > $total_pages) $page=$total_pages;
$start = $limit*$page - $limit; // do not put $limit*($page - 1)
$SQL = "SELECT id, dataplecare, orasplecare, orasdestinatie, username FROM marfa ORDER BY $sidx $sord LIMIT $start , $limit";
$result = mysql_query( $SQL ) or die("Couldn t execute query.".mysql_error());
$responce->page = $page;
$responce->total = $total_pages;
$responce->records = $count;
$i=0;
while($row = mysql_fetch_array($result,MYSQL_ASSOC)) {
$responce->rows[$i]['id']=$row[id];
$responce->rows[$i]['cell']=array($row[id],$row[dataplecare],$row[orasplecare],$row[orasdestinatie],$row[username]);
$i++;
}
echo json_encode($responce);
?>

The problem is the table is rendered empty. If anybody has some suggestions please show me the way...

jQuery Grid Plugin - jqGrid - Topic: jqgrid help - php json fill table

ggcristian on jqgrid help - php json fill table

ggcristian on jqgrid help - php json fill table