jQuery Grid Plugin - jqGrid - Topic: How to define a new grid without a column? http://www.trirand.com/blog/?page_id=393/help/how-to-define-a-new-grid-without-a-column Simple:Press Version 5.7.5.3 ivanchain on How to define a new grid without a column? http://www.trirand.com/blog/?page_id=393/help/how-to-define-a-new-grid-without-a-column#p15603 Help http://www.trirand.com/blog/?page_id=393/help/how-to-define-a-new-grid-without-a-column#p15603 Thank you so much. In fact.... my problem is /blog/?page_id=393/help/jgrid-confict-with-dnn/#p15600, I start a new topic.

sorry....

yours,

ivan

]]> Thu, 11 Mar 2010 12:17:14 +0200 lupin on How to define a new grid without a column? http://www.trirand.com/blog/?page_id=393/help/how-to-define-a-new-grid-without-a-column#p15599 Help http://www.trirand.com/blog/?page_id=393/help/how-to-define-a-new-grid-without-a-column#p15599 Ok thats good, now what you want to achieve or the problem you're having? Loading data to grid using ArrayData?

This word "#list" on  jQuery("#list") is the id table tag where you grid will be define.

hth,

lupin

]]> Thu, 11 Mar 2010 11:29:26 +0200 ivanchain on How to define a new grid without a column? http://www.trirand.com/blog/?page_id=393/help/how-to-define-a-new-grid-without-a-column#p15596 Help http://www.trirand.com/blog/?page_id=393/help/how-to-define-a-new-grid-without-a-column#p15596 Yes, of cause, I have make the basic example to work.

yours,

Ivan

]]> Thu, 11 Mar 2010 11:15:58 +0200 lupin on How to define a new grid without a column? http://www.trirand.com/blog/?page_id=393/help/how-to-define-a-new-grid-without-a-column#p15595 Help http://www.trirand.com/blog/?page_id=393/help/how-to-define-a-new-grid-without-a-column#p15595 What exactly is the problem you have? Perhaps you start here http://www.trirand.com/jqgridw.....first_grid and work make it work first then customise it later once you had it working.

hth,

lupin

]]> Thu, 11 Mar 2010 10:54:34 +0200 ivanchain on How to define a new grid without a column? http://www.trirand.com/blog/?page_id=393/help/how-to-define-a-new-grid-without-a-column#p15591 Help http://www.trirand.com/blog/?page_id=393/help/how-to-define-a-new-grid-without-a-column#p15591 hello,

I see the /jqgridwiki/doku.php?id=wiki:retrieving_data.  It show how to use a local array data, and it said:

-----------------------------

<script> jQuery(document).ready(function(){
    jQuery("#list").jqGrid({
        datatype: 'clientSide',
        colNames:['Inv No','Date', 'Amount','Tax','Total','Notes'], colModel :[
        {name:'invid',index:'invid', width:55, sorttype:'int'},
        {name:'invdate',index:'invdate', width:90, sorttype:'date', datefmt:'Y-m-d'},
        {name:'amount',index:'amount', width:80, align:'right',sorttype:'float'},
        {name:'tax',index:'tax', width:80, align:'right',sorttype:'float'},
        {name:'total',index:'total', width:80,align:'right',sorttype:'float'},
        {name:'note',index:'note', width:150, sortable:false} ],
        pager: '#pager',
        rowNum:10,
        viewrecords: true,
        caption: 'My first grid'
   });
...
});
</script>

-----------------------------

But, I think I need to have a grid on the page, then I could use  jQuery("#list") to find it.

So I define a grid like this:

--------------------------

 <trirand:JQGrid ID="jqGrid3" runat="server">        
        </trirand:JQGrid>

--------------------------

But at running time, it always report an error that there is needed a column at least. But I am adding the column use array in the  jQuery("#list") code above? What's it mean?

yours,

Ivan

]]> Thu, 11 Mar 2010 09:57:05 +0200