tony on 2 Questions about jqGrid (Subgrid) and json(string)

Thu, 13 Aug 2009 01:56:41 +0300

Hello,

About the second question.

The addRowData currently does not support this. I suggest you to use datatype as function - see docs and addJSONData method to add data. This method support this named convention.

Regards

Tony

tony on 2 Questions about jqGrid (Subgrid) and json(string)

Thu, 13 Aug 2009 01:53:04 +0300

Hello,

http://www.trirand.com/jqgridw.....id#methods

One note (which I will correct into the docs)

If you use subGridJson you should use the method this way:

var mygrid = jQuery("#mygrid")[0];

mygrid.subGridJson(arraydata,rowid)

Arne on 2 Questions about jqGrid (Subgrid) and json(string)

Tue, 11 Aug 2009 10:08:44 +0300

Hi everybody

I'm developping a web application with Java, Springframework, DWR and JQuery.

My first grid was successful.

$("#sortable").jqGrid({
   datatype: 'jsonstring',
   userdata: mydata,
   colNames:[
     '<spring:message code="label"/>',
     '<spring:message code="label"/>'
   ],
   colModel:[
     { name:'field1', index:'field1', sortable:true, sorttype:'int' },
     { name:'field2', index:'field2', sortable:false }
   ],
   emptyrecords: "<spring:message code="label"/>",
   hoverrows: true,
   toolbar: [true, "bottom"],
   width: 653,
   height: 300
});

var mydata = [
   <c:forEach var="item" items="${listAsJson}" varStatus="status">
     <c:choose>
       <c:when test="${status.last}">
         ${item}
       </c:when>
       <c:otherwise>
         ${item},
       </c:otherwise>
     </c:choose>
</c:forEach>
];

for(var i=0;i<=mydata.length;i++) {
$("#sortable").addRowData(i+1,mydata[i]);
}

But now I need some sub grids.

The problem is, that I don't know, how to add the rows into the sub grid. I still have all datas in the response (I'm looking for the datas in the previous Spring-Controller and add them into the request).

The second question is about json. I have objects in objects. The json string looks ok, or doesn't it?

{ "name": "test", "phone": "111", "address": { "street": "street" } }

But if I change the ColModel to:

colModel:[
{ name:'address.street', index:'address.street' }
],

I don't get any results.

It makes me ... :S

Best regards

Arne

jQuery Grid Plugin - jqGrid - Topic: 2 Questions about jqGrid (Subgrid) and json(string)

tony on 2 Questions about jqGrid (Subgrid) and json(string)

tony on 2 Questions about jqGrid (Subgrid) and json(string)

Arne on 2 Questions about jqGrid (Subgrid) and json(string)