var c = b.extend({}, b(this).jqGrid("getGridParam"));

With this:

var c = b.extend(true, {}, b(this).jqGrid("getGridParam"));

The difference is that the latter option makes a deep copy, instead of a shallow one.

This should not happen since of this,

var c = b.extend({}, b(this).jqGrid("getGridParam"));

but I will check it.

Regards

Tony

I have multiselect: true, which when I called jqGridExport

the actual colModel and colName was splice also. I highlight the code in purple.

Is there a way to duplicate the object  instead of using the actual object?

jqGridExport: function(a){

a = b.extend({ exptype:

"xmlstring", root: "grid", ident: "\t" }, a || {}); var e = null; this.each(function() {

if (this.grid) {

var c = b.extend({}, b(this).jqGrid("getGridParam"));

if (c.rownumbers) { c.colNames.splice(0, 1); c.colModel.splice(0, 1) }

 if (c.multiselect) {

c.colNames.splice(0, 1); c.colModel.splice(0, 1)

}

if (c.subgrid) {

c.colNames.splice(0,1); c.colModel.splice(0, 1)

}

if (c.treeGrid) for (var j in c.treeReader) { c.colNames.splice(c.colNames.length - 1); c.colModel.splice(c.colModel.length - 1) } switch (a.exptype) { case "xmlstring": e = "<" + a.root + ">" + xmlJsonClass.json2xml(c, a.ident) + "</" + a.root + ">"; break; case "jsonstring": e = "{" + xmlJsonClass.toJson(c, a.root, a.ident) + "}"; if (c.postData.filters != undefined) { e = e.replace(/filters":"/, 'filters":'); e = e.replace(/}]}"/, "}]}") } break }

}

});

return e

},

I tried to download all the files again but it still the same.

Here are the js files I am using:

jquery-1.3.2.min.js

i18n/grid.locale-en.js

jquery-ui-1.7.2.custom.min.js

jquery.jqGrid.min.js

Which version is used?

Try with the latest one.

regards

Tony

here's my function:

$(

"#ExportMe").click(function() {

var s;

s = jQuery(

"#list1").jqGrid('jqGridExport', { exptype: 'xmlstring', root: 'grid', ident: '\t' });

});