Thank you for this - you are right.

There is a more easy way to do that. Just move this piece of code

before adding the subgrid and multiselect columns in the

colModel

Regards

Tony

Are you sure this isn't a bug?

With the following configuration:

jQuery("#mygrid").jqGrid({
	datatype: "json",
   	colNames:['#','Name'],
   	colModel:[
   		{name:'id',index:'id', width:60, key:true},
   		{name:'name',index:'name', width:120}
	],
	subGrid: false,
	...

If subGrid is false, the 'id' column will be the key column.

However, if subGrid is true, the 'name' column will become the key column, which is not correct is it?

Modifying the code in grid.base.js (line 1147ff) with a decrement if subGrid is set resolves this:

for (var i=0; i<ts.p.colModel.length;i++) {
	if (ts.p.colModel[i].key===true) {
		if (ts.p.subGrid) i--;
		ts.p.keyIndex = i;
		break;
	}
}

This is discussed before. It is not a bug. If you look into the code above this fragment you will find the answer. The subgrid column is added before this.

Regards

Tony

incorrect calculate parametr keyIndex (order number of fields with "key: true")

Reason: 

look code. If "subGrid: true" then first element in ts.p.colModel is cell for subgrid. and keyIndex will set more for one. 

for (var i=0; i<ts.p.colModel.length;i++) {

if (ts.p.colModel[i].key===true) { ts.p.keyIndex = i;