This definitley works for me. Tested. Check to see which modules do you have downloaded.

Regards

Tony

(Version Jqgrid: 3.6.2)

<link rel="stylesheet" type="text/css" media="screen" href="css/ui-lightness/jquery-ui-1.7.2.custom.css" />

<link rel="stylesheet" type="text/css" media="screen" href="css/ui.jqgrid.css" />

<script src="js/jquery-1.3.2.min.js" type="text/javascript"></script>

<script src="js/i18n/grid.locale-en.js" type="text/javascript"></script>

<script src="js/jquery.jqGrid.min.js" type="text/javascript"></script>

<script src="js/src/grid.jqueryui.js" type="text/javascript"></script>

<script type="text/javascript">

jQuery(document).ready(function(){ 

  jQuery("#list").jqGrid({

sortable: true,

    url:'example.php',

    datatype: 'xml',

    mtype: 'GET',

    colNames:['Inv No','Date', 'Amount','Tax','Total','Notes'],

    colModel :[ 

      {name:'invid', index:'invid', width:55}, 

      {name:'invdate', index:'invdate', width:90}, 

      {name:'amount', index:'amount', width:80, align:'right'}, 

      {name:'tax', index:'tax', width:80, align:'right'}, 

      {name:'total', index:'total', width:80, align:'right'}, 

      {name:'note', index:'note', width:150, sortable:false} 

    ],

    pager: '#pager',

    rowNum:10,

    rowList:[10,20,30],

    sortname: 'invid',

    sortorder: 'desc',

    viewrecords: true,

    caption: 'My first grid'

  }); 

}); 

Thanks.